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Mashcka [7]
3 years ago
15

The number nine added to the product of 7 and -10 is what number?

Mathematics
1 answer:
wel3 years ago
7 0

Answer:

53

Step-by-step explanation:

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Plz help me well mark brainliest if correct,.........??
Oksanka [162]

Answer: A

Step-by-step explanation:

Because to find the area I multiplied and got 72 then I looked up how to find them perimeter

4 0
3 years ago
Read 2 more answers
Can someone help me with these 4 questions
olya-2409 [2.1K]
15. 145. 360-90-95-30
16. 90

The other picture number 16 again I already did that one.
4 0
3 years ago
F(x) = (x - 2)²(x+1)​
Inessa [10]

(x - 2)²(x+1)​

(x-2)(x-2)

multiply the two brackets together

(x)(x)=x^2

(x)(-2)=-2x

(-2)(x)=-2x

(-2)(-2)=4

x^2-2x-2x+4

x^2-4x+4

(x^2-4x+4)(x+1)

multiply the brackets together

(x^2)(x)=x^3

(x^2)(1)=x^2

(-4x)(x)=-4x^2

(-4x)(1)=-4x

(4)(1)=4

x^3+x^2-4x^2-4x+4x+4

Answer:

x^3-3x^2+4

5 0
4 years ago
At the ice cream parlor there are thirty flavors, but for the last week they have only had 25 flavors.
myrzilka [38]

Answer: Percent change = 20%

===========================================================

Work Shown:

A = old value = 25 (last week's number)

B = new value = 30 (current week's number)

C = percent change

C = [ (B-A)/A ] * 100%

C = [ (30-25)/25 ] * 100%

C = [ 5/25 ] * 100%

C = 0.20* 100%

C = 20%

The percent change is 20%

The positive value of C indicates we have a percent increase.

8 0
3 years ago
Having serious block because of the units The density of mercury is 13.6 g/cm3. What approximate mass of mercury is required to
mart [117]
I would approach the problem like this:

1 oz bottle.............................30cm^3
33 oz bottle.............................xcm^3

in a 33 oz bottle will be x=33*30=990cm^3
density=mm/v
13.6g/cm^3= m/ 990cm^3
m= 13.6 * 990=13464 g
or 13.464 kg in a 33 oz bottle
3 0
3 years ago
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