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finlep [7]
3 years ago
10

A utility company charges $0.12 per kilowatt-hour for energy a customer uses.They give a credit of $0.0025 for every kilowatt-ho

ur of electricity a customer with a solar panel generates that they don't use themselves.A customer has a charge of $82.04 and a credit of -$4.10 on this mouth bill. How many kilowatt-hour did they generate that they didn't use themselves?
Mathematics
1 answer:
Vilka [71]3 years ago
5 0

Answer:

What is the amount due this month? $77.94

Page Break

How many kilowatt-hours did they use? 686 2/3

How many kilowatt-hours did they generate that they didn't use themselves? 34 1/6

Step-by-step explanation:

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(5 - 7i)(8 + i)

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Step-by-step explanation:

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3 years ago
Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
Nataly_w [17]

Answer:

The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

coefficient of x^{2} in the expansion of (2+x - x^{2})^{6} = (240 - 192) = 48

Step-by-step explanation:

(2+x)^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})

= 6_{C_{0}} \times x^{0} \times 2^{6}  + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4} + terms involving higher powers of x

= 64 + 192 \times x^{1} + 240 \times x^{2} + terms involving higher powers of x

so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

Again,

(2+x - x^{2})^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})

Now, by inspection,

the term x^{2} comes from k =5 and k = 6

for k = 5, the coefficient of  x^{2}  is , (-32) \times 6 = -192

for k = 6 , the coefficient of x^{2} is, 6_{C_{2}} \times 2^{4} = 240

so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

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2 years ago
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3 years ago
Find the zeros : x(x^2+13x+40)
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The zeros are x= 0,-5,-8. the zeros are the x values where the graph intersects the x-axis. to find the zeros, you have to replace y with zero then solve for x.
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3 years ago
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