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2 years ago

I need some help out with a question!

Mathematics

1 answer:

Alika [10]2 years ago

3 0

Answer:

Here is your answer plz mark as brainliest

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Help me please I don’t know what to do what’s the answer

shtirl [24]

YAY!!! ANOTHER PERSON FRON ED-GENUITY!!!
All of the letters are equal to 90 degrees so the answer would be C.
Hope I helped!

7 0

2 years ago

A train leaves a station and travels north at a speed of 105105 km/h. twotwo hours later, a second train leaves on a parallel

hram777 [196]

Let x = hours to meet

train one has a 2 hour head start or 210 km head start

210 + 105x = 135x
30x = 210
x = 7 hours to meet

6 0

3 years ago

On-the-Go Phone Company has two monthly plans for their customers. The EZ Pay Plan costs $0.15

ddd [48]

Answer:

a. 0.15x

b. 40+0.05x

c. 0.15x=40+0.05x

15x=4000+5x

x=400 min

6 0

2 years ago

Subtract<br> 505,000 - 427,619 -

yawa3891 [41]

Answer:

77381 is your answer

Step-by-step explanation:

5 0

2 years ago

The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 1

evablogger [386]

Answer:

The 98% confidence interval for the population mean number of hours worked per year per person is (2146, 2193).

Step-by-step explanation:

The question is incomplete.

The number of hours registered in the sample are:

2051 2061 2162 2167 2169 2171

2180 2183 2186 2195 2196 2198

2205 2210 2211

The sample mean can be calculated as:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{15}(2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)\\\\\\M=\dfrac{32545}{15}\\\\\\M=2169.67\\\\\\$

We have to calculate a 98% confidence interval for the mean.

The population standard deviation is know and is σ=39.

The sample mean is M=2169.67.

The sample size is N=15.

As σ is known, the standard error of the mean (σM) is calculated as:

$\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{39}{\sqrt{15}}=\dfrac{39}{3.873}=10.07$

The z-value for a 98% confidence interval is z=2.326.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_M=2.326 \cdot 10.07=23.43$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 2169.67-23.43=2146\\\\UL=M+t \cdot s_M = 2169.67+23.43=2193$

The 98% confidence interval for the population mean is (2146, 2193).

3 0

3 years ago