Answer:
Increasing on it's domain 
because the slope is positive.
The domain and range are both all real numbers, also known as
.
Step-by-step explanation:
All domain really means is what numbers can you plug in and you get number back from your function.
I should be able to plug in any number into 3x+2 and result in a number. There are no restrictions for x on 3x+2.
The domain is all real numbers.
In interval notation that is .
Now the range is the set of numbers that get hit by y=3x+2.
Well y=3x+2 is a linear function that is increasing. I know it is increasing because the slope is positive 3. I wrote out the positive part because that is the item you focus on in a linear equation to determine if is increasing or decreasing.
If slope is positive, then the line is increasing.
If slope is negative, then the line is decreasing.
So y=3x+2 hits all values of y because it is increasing forever. The range is all real numbers. In interval notation that is .
Answer: The car travels 97.5 miles in 1.5 hour.
Step-by-step explanation:
Given: A car is traveling down a highway at a constant speed, described by the equation , described by the equation 
, where represents the distance, in miles, that the car travels at this speed in<em> t</em> hours.
To find : Number of miles car travel in 1.5 hour.
Simply put t= 1.5 in the given expression , we get
65(1.5)= 97.5
That means , the car travels 97.5 miles in 1.5 hour.
Answer:
F, J, K
Step-by-step explanation:
The other choices are regarded as expressions not equations, in which you can find the value of the the given variable.
This is an arithmetic sequence with the common difference being 1
and if u have 1 cent on day 1 and 2 cents on day 2....then on day 40, u would have 40 cents....but we need the sum of all the days..
the sum of an arithmetic sequence can be found using the formula :
sn = n(a1 + an) / 2
n = number of terms = 40
a1 = first term = 1
an = last term = 40
now we sub
s(40) = 40(1 + 40) / 2
s(40) = 40(41)/2
s(40) = 1640/2
s(40) = 820.....820 cents = $ 8.20 <== the sum
Hmmmmmmmmmmmmmmmmmmmmmmmmmm
