All categories

3 years ago

"Classical" in the context of the Renaissance, means ...

Mathematics

2 answers:

gayaneshka [121]3 years ago

7 0

D. becuase i know history

ipn [44]3 years ago

7 0

A because that just makes more sense

You might be interested in

The area of a trapezium shaped field is 480m^2,the distance between two parallel

meriva

Answer:

Area of trapezium = 1/2 * h (a+b)

here, 480= 1/2 *15*(20+b)

(20+b)=960/15

or, b=64-20

therefore, b= 44

.....

Hope u got it...xd

3 0

3 years ago

gregori [183]

It’s D bc Dt= 15x3 and it’s not that hard to solve

6 0

4 years ago

Describe a real-world situation that the graph could represent. Then describe the possible values for each variable

Alex777 [14]

Answer:

$Speed=distance/time$ i.e. relation between speed-distance-time is one such situation that can be modeled using graph

Step-by-step explanation:

There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.

One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.

So, the equation for speed is represented by equation as follows:

$Speed=distance/time$

So, if we take distance on y axis and time on x axis with points as (distance,time)

(0,0) ==> $v=0/0=0$

(1,2) ==> $v=1/2=0.5$

(2,2) ==> $v=2/2=1$

the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.

8 0

3 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

4 years ago

C x 34 = <br><br> Show Your work

Brut [27]

Answer:

C x 34 or 34c

Step-by-step explanation:

There isn't really a way to show work or really an answer unless you have a value for C but I hope this helped anyway.

3 0

3 years ago

Read 2 more answers