Which expression is equivalent to this one?<br> j-6+j•s<br> O6+)<br> O6+)<br> D3(6+):s

What is the probability that the spinner lands on an even number or on the unshaded section? one-fifth two-fifths three-fifths f

Tasya [4]

The probability that the spinner lands on an even number or on the unshaded section is; 3/5

<h3>How to find the probability?</h3>

From the spinner attached, we see that the number of sections on the spinner is 5 sections.

Now, we can also see that;

Number of even numbers section = 2

Number of shaded sections = 1

Thus, probability that the spinner lands on an even number or on the unshaded section is;

P(even number or unshaded section) = (2 + 1)/5 = 3/5

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5 0

2 years ago

W is the midpoint of VX. What is VX if VW=2x+5 and WX =4x-3

Novosadov [1.4K]

Answer:

Step-by-step explanation:

If W is the midpoint of VX then VW = WX. Therefore we have the equation:

2x + 5 = 4x - 3 <em>subtract 5 from both sides</em>

2x = 4x - 8 <em>subtract 4x from both sides</em>

-2x = -8 <em>divide both sides by (-2)</em>

x = 4

VX = VW + WX

VX = 2x + 5 + 4x - 3 = (2x + 4x) + (5 - 3) = 6x + 2

Put the value of x = 4 to 6x + 2:

VX = 6(4) + 2 = 24 + 2 = 26

7 0

3 years ago

10 points please answer correctly (due soon)

luda_lava [24]

The exponential equation of the model is A(t) = 2583 * 0.88^t and the multiplier means that the number of new cases in a week is 88% of the previous week

<h3>The function that models the data</h3>

The given parameters are:

New, A(t) = 2000

Rate, r = 12%

The function is represented as:

A(t) = A * (1 - r)^t

So, we have:

2000 = A * (1 - 12%)^t

This gives

2000 = A * (0.88)^t

2 weeks ago implies that;

t = 2

So, we have:

2000 = A * 0.88^2

Evaluate

2000 = A * 0.7744

Divide by 0.7744

A = 2583

Substitute A = 2583 in A(t) = A * 0.88^t

A(t) = 2583 * 0.88^t

Hence, the exponential equation of the model is A(t) = 2583 * 0.88^t

<h3>The interpretation of the multiplier</h3>

In this case, the multiplier is 88% or 0.88

This means that the number of new cases in a week is 88% of the previous week

Read more about exponential equation at

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8 0

2 years ago

Suppose that scores on the mathematics part of a test for eighth-grade students follow a Normal distribution with standard devia

riadik2000 [5.3K]

Answer:

We need an SRS of scores of at least 153.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large an SRS of scores must you choose?

This is at least n, in which n is found when $M = 20, \sigma = 150$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$20 = 1.645*\frac{150}{\sqrt{n}}$

$20\sqrt{n} = 1.645*150$

$\sqrt{n} = \frac{1.645*150}{20}$

$\sqrt{n} = 12.3375$

$(\sqrt{n})^{2} = (12.3375)^{2}$

$n = 152.2$

Rounding to the next whole number, 153

We need an SRS of scores of at least 153.

8 0

3 years ago

25 points!! help me out plssss

hodyreva [135]

What is the question? It doesn’t show

6 0

3 years ago

Which expression is equivalent to this one? j-6+j•s O6+) O6+) D3(6+):s