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Savatey [412]
3 years ago
9

What is the right answer?

Mathematics
2 answers:
const2013 [10]3 years ago
7 0

Answer:

The answer would be: B- X

Step-by-step explanation:

It would be X because you just count how many feeders and put it over the amount of birds.

trapecia [35]3 years ago
6 0
Dot Plot X is correct

Because the numbers match
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7 0
3 years ago
A sphere with center A is shown. Which represents a radius?
Lunna [17]
A because radius is half of the diameter
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What is the perimeter of the figure to the nearest tenth of a millimeter?
Pavlova-9 [17]
We have to calculate the perimeter of the figure to the nearest tenth of a millimeter. This figure is made of a rectangle and a half of a circle. The first figure has the perimeter: 3 + 6 + 3 = 12 mm. The second figure has the perimeter: 2 * Pi * r / 2 = Pi * r ; and the radius : r = 6/2 = 3 mm. So Pi * 3 = 3.14 * 3 = 9.42. Fimally : 12 + 9.42 = 21.42 or 21.4 to the nearest tenth. Answer: C. 21.4 millimeters<span>. </span>
7 0
3 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

                                    =(0.70)^{3}\\=0.343

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

                                   =1-0.343\\=0.657

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

                         = P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

                              + P (Only 3rd vehicle passes)

                       =(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

                                                       + P (0 vehicles passes)

                                              =0.189+(0.30\times0.30\times0.30)\\=0.216

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0
3 years ago
GEOMETRY QUESTION W PICTURE
dmitriy555 [2]

Answer:

R

Step-by-step explanation:

E is congruent to R because of angle stuff

6 0
2 years ago
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