We are given the equation y = 2(x – 3)^2 – 4 and is asked for the domain and range of the following function. In this case, there is no radical sign so the domain includes all real numbers. The range has a minimum value of -4 since the squaring makes the value on the first term positive. Hence the answer is A.
Answer:
Circumscribed circle: Around 80.95
Inscribed circle: Around 3.298
Step-by-step explanation:
Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

To find the area of the circumscribed circle:

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

The area of the triangle is:

The semiperimeter of the triangle is:

The radius of the circle is therefore 
The area of the inscribed circle then is
.
Hope this helps!
Answer:
The slope is -3
Step-by-step explanation:
The formula is y= mx + b
m = slope
b= y intercept
Therefore, the slope is -3
Mukat gets 40, Usha gets 8
Step-by-step explanation:
Mukat = 5 × Usha
After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)
Then Mukat = final number of books for Usha
5 × Usha - 16 = Usha + 16
(5 × Usha ) - Usha = 16+16
4 × Usha = 32
Usha = 8 i.e her number of books.
Mukat = 5×8=40.
I HOPE IT'S OK
Answer:
x+6
Step-by-step explanation: