3 years ago

Write the equation of the line that passes through the points (4,7) and (8,6). Put

1 answer:

8 0

Y=-1/4x+8

First find the slope

Slope= y-y1/x-x1

So (6-7)/(8-4) = -1/4

Now take that slope and use one of the points and plug them into the point slope formula to solve for your y intercept.

Point slope formula: y=mx+b

So 7=-1/4(4)+b OR 6=-1/4(8)+b

Either way you’ll get b=8!

Put em together and you get: y=-1/4x+8

Ps you can double check your answer by plugging in one or both of the points into your equation to see if it works :)

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Solve the equation y=2x^2-x-6 using the quadratic formula show the steps to solving

saul85 [17]

Answer:

$x1 = 2 \\ x2 = - \frac{3}{2}$

Step-by-step explanation:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{1 + - \sqrt{ {( - 1)}^{2} - 4(2)( - 6) } }{2(2)} \\ x = \frac{1 + - \sqrt{1 + 48} }{4} \\ x = \frac{1 + - \sqrt{49} }{4} \\ x = \frac{1 + - 7}{4} \\ \\ x1 = \frac{1 + 7}{4} = \frac{8}{4} = 2 \\ x2 = \frac{1 - 7}{4} = - \frac{6 }{4} = - \frac{3}{2}$