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3 years ago

Find the x and y intercepts of the graph of the equation y=x^2-5

Mathematics

1 answer:

mr_godi [17]3 years ago

8 0

Answer:

x intercepts -sqrt(5), + sqrt(5)

y intercept -5

Step-by-step explanation:

y = x^2 -5

to find the x intercept set y=0 and solve for x

0 = x^2-5

add 5 to each side

5 = x^2

take the square root of each side

+- sqrt(5) = sqrt(x^2)

x = +-sqrt(5) there are 2 x intercepts since it is a quadratic

to find the y intercept set x=0 and solve for y

y = 0-5

y = -5

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------------------------------------------------------------------
Question
------------------------------------------------------------------
$\boxed { \frac{n+h}{5} = \frac{f+9}{9}}$

------------------------------------------------------------------
Split the fraction on the left
------------------------------------------------------------------
$\boxed { \frac{n}{5} + \frac{h}{5} = \frac{f + 9}{9}}$

------------------------------------------------------------------
Take away h/5 from both sides
------------------------------------------------------------------
$\boxed { \frac{n}{5} = \frac{f+9}{9} - \frac{h}{5}}$

------------------------------------------------------------------
Change the denominator to be the same
------------------------------------------------------------------
$\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}$

------------------------------------------------------------------
Put it into single fraction
------------------------------------------------------------------
$\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }$

-------------------------------------------------------------------
Rearrange (This step may not be necessary)
------------------------------------------------------------------
$\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }$

$\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}$

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