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vladimir1956 [14]
3 years ago
12

Assume that there are two pairs of congruent triangles in the diagram shown.

Mathematics
1 answer:
cluponka [151]3 years ago
8 0

Answer: True

Step-by-step explanation:

If the triangles are congruent it means they are the same therefore ROB is congruent to PTA

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The area of a triangular-shaped rug is 21 square yards and the height is 3 yards. Find the base.
tresset_1 [31]

Answer:

14 yards

Step-by-step explanation:

the area of a triangle is 0.5×b×h

so

plug in what you have

0.5×b×3=21

(3x0.5)b=21

1.5b=21

b=21/1.5

b=14

6 0
3 years ago
PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!
Burka [1]

Answer:

B) Angle 2 and Angle 3

Step-by-step explanation:

Angle 2 and Angle 3 are equal since they're vertical angles and aren't supplementary

Angle 7 and 8 are supplementary

Angle 1 and 7 are supplementary

Honestly, i have no clue with angle 4 and angle 4. I just know that vertical angles aren't supplementary because they're equal to each other so I'll assume this is the case as well.

4 0
3 years ago
Opposite reciprocal slope lines or parallel or perpendicular
GarryVolchara [31]


-- If two lines on a graph are parallel, then their slopes are equal.

-- If two lines on a graph are perpendicular, then their slopes are
negative reciprocals.


6 0
3 years ago
Sergey is solving 5x2 + 20% – 7 = 0. Which steps could he use to solve the quadratic equation by completing the
Mrac [35]

Answer:

5(x^2+4x)=7

5(x^2+4x+4)=7+20

(x+2)=\pm\sqrt{\frac{27}{5}}

Step-by-step explanation:

we have

5x^2+20x-7=0

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

5x^2+20x=7

step 2

Factor 5 left side

5(x^2+4x)=7

step 3

Complete the square

5(x^2+4x+2^2)=7+2^2(5)

5(x^2+4x+4)=7+20

5(x^2+4x+4)=27

step 4

Rewrite as perfect squares

5(x+2)^2=27

step 5

(x+2)^2=\frac{27}{5}

(x+2)=\pm\sqrt{\frac{27}{5}}

(x+2)=\pm\frac{3\sqrt{15}}{5}

step 6

x=-2\pm\frac{3\sqrt{15}}{5}

6 0
4 years ago
Read 2 more answers
Logx(8x-3)-logx 4=2<br> please help ill give you everything i have !!
Gelneren [198K]
Logx (8x-3) - logx 4 = 2
logx [(8x-3)/4] = 2
x^2=(8x-3)/4
4x^2=4(8x-3)/4
4x^2=8x-3
4x^2-8x+3=8x-3-8x+3
4x^2-8x+3=0
4(4x^2-8x+3=0)
(4^2)(x^2)-8(4x)+12=0
(4x)^2-8(4x)+12=0
(4x-2)(4x-6)=0
2(4x/2-2/2)2(4x/2-6/2)=0
4(2x-1)(2x-3)=0
4(2x-1)(2x-3)/4=0/4
(2x-1)(2x-3)=0
Two options:
1) 2x-1=0
2x-1+1=0+1
2x=1
2x/2=1/2
x=1/2

2) 2x-3=0
2x-3+3=0+3
2x=3
2x/2=3/2
x=3/2

Answer: Two solutions: x=1/2 and x=3/2
6 0
3 years ago
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