Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
Answer:
Step-by-step explanation:
27^1/3
27 is cube root of 3
so it can also be written as (3)^3
∴ {(3)^3}^1/3
3 and 3 will get cancelled
so it will be 3^1
= 3
It is in the thousandths place.
You just multiply the numbers and if it’s less than that number you it it in the bud hood this helps!
Answer:
It isn't necessary but having a positive coefficient for
makes things like completing the square and factoring easier.