Answer:
Step-by-step explanation:
The general formula for this sequence is a(n) = a(1)*(-1/4)^(n - 1). We don't yet know a(1).
If a(3) = 128, then 128 = a(1)*(-1/4)^(3 - 1), or
128 = a(1)*(1/16)
and so a(1) = 128/16
resulting in the specific formua a(n) = 8(-1/4)^(n - 1)
Now let's find a(7):
a(7) = 8(-1/4)^1 * (-1/4)^(6)
or
a(7) = 8(-1/4)^7
Answer:
Decay
Step-by-step explanation:
Answer: x=7 and AC = 44 unuts.
Step-by-step explanation:
We know that the diagonals of a parallelogram bisect each other. (i)
Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.
BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6
Using (i)
Now , AE = 4(7)-6 = 28-6 = 22
AC =2 AE = 2 (22) =44 units.
Hence, x=7 and AC = 44 unuts.
I think the answer is 1/2. C.
Hello from MrBillDoesMath!
Answer:
a(n) = (-n)^3 where n = 1,2,3,...
Discussion:
The pattern 1,8,27, 64... is immediately recognizable as the the cube of the positive integers. But this question has a minus sign appearing before each entry, suggesting we try this:
- 1 = (-1)^3
-8 = (-2)^3
-27 = (-3)^3
-64 = (-4)^3
That's what the problem statement asked for
. The answer is equivalently
-1 * (n^3)
Thank you,
MrB
