3 years ago

Formula to find base of a triangle

Mathematics

1 answer:

ohaa [14]3 years ago

8 0

Answer:

b=2 A/a sin γ

Step-by-step explanation:

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nata0808 [166]

Answer:

$\displaystyle 18,28 ≈ x$

Step-by-step explanation:

$\displaystyle \frac{x}{11} = csc\:37 \hookrightarrow 11csc\:37 = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x$

$\displaystyle \frac{11}{x} = sin\:37 \hookrightarrow xsin\:37 = 11 \hookrightarrow \frac{11}{sin\:37} = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x$

Information on trigonometric ratios

$\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ$