Answer:
1. sum of term = 465
2. nth term of the AP = 30n - 10
Step-by-step explanation:
1. The sum of all natural number from 1 to 30 can be computed as follows. The first term a = 1 and the common difference d = 1 . Therefore
sum of term = n/2(a + l)
where
a = 1
l = last term = 30
n = number of term
sum of term = 30/2(1 + 30)
sum of term = 15(31)
sum of term = 465
2.The nth term of the sequence can be gotten below. The sequence is 20, 50, 80 ......
The first term which is a is equals to 20. The common difference is 50 - 20 or 80 - 50 = 30. Therefore;
a = 20
d = 30
nth term of an AP = a + (n - 1)d
nth term of an AP = 20 + (n - 1)30
nth term of an AP = 20 + 30n - 30
nth term of the AP = 30n - 10
The nth term formula can be used to find the next term progressively. where n = number of term
The sequence will be 20, 50, 80, 110, 140, 170, 200..............
Answer:
after 1 Min it's -9
after 2 mins it's -1.08
Step-by-step explanation:
12% X 75 = 9
12% X 9 = 1.08
Answer:
7m² - 5m + 8 + 3/(m+3)
Step-by-step explanation:
7m³+16m²-7m+27
(7m³+21m²-5m²-15m+8m+24+3)/(m+3)
[7m²(m+3) - 5m(m+3) + 8(m+3) + 3]/(m+3)
7m² - 5m + 8 + 3/(m+3)
You would do 200 times 1.58 and that gets you 316 hope this helps :)
