Question

What is the slope y+2=1/4(x-3)

Answer 1

Answer:

$m=\frac{1}{4}$

Step-by-step explanation:

Given

$y+2=\frac{1}{4}(x-3)$

Required

Find the slope

$y+2=\frac{1}{4}(x-3)$

Subtract 2 from both sides

$y+2-2=\frac{1}{4}(x-3) - 2$

$y=\frac{1}{4}(x-3) - 2$

Open bracket

$y=\frac{1}{4}x-\frac{1}{4}*3 - 2$

$y=\frac{1}{4}x-\frac{3}{4} - 2$

Take LCM

$y=\frac{1}{4}x+\frac{-3 - 8}{4}$

$y=\frac{1}{4}x+\frac{-11}{4}$

$y=\frac{1}{4}x-\frac{11}{4}$

An equation has the form:

$y = mx + b$

Where

$m = slope$

By comparing: $y = mx + b$ and $y=\frac{1}{4}x-\frac{11}{4}$

$m=\frac{1}{4}$

So, the slope is 1/4