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dem82 [27]
3 years ago
5

3x-2y<10 in a graph graphing linear equalities

Mathematics
1 answer:
faltersainse [42]3 years ago
5 0

Answer:

I hope it will help you!

Step-by-step explanation:

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Two tracking stations are on the equator 148 miles apart. A weather balloon is located on a bearing of N41°E from the western st
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Answer:

  A  404 mi

Step-by-step explanation:

If we designate the points of the triangle A, B, and C for the locations of the western station, eastern station, and balloon, respectively, we have the following:

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  ∠CBA = 90° + 21° = 111°

  ∠ACB = 41° -21° = 20°

side "c" (opposite ∠ACB) is 148 miles

The distance we're asked to find is AC = b, the longest side of the triangle. The law of sines tells us ...

  b/sin(B) = c/sin(C)

  b = c·sin(B)/sin(C) = (148 mi)·sin(111°)/sin(20°) ≈ 403.98 mi ≈ 404 mi

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3 years ago
The hypotenuse of a right triangle is 7 inches longer than the base and 14 inches longer than the height. the permeter of the tr
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To determine the area of a triangle, we calculate one half of the product of the base and the height of the triangle so we need data on its base and its height. We are given the following:

Hypotenuse = 7 + base = 14 + height
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The perimeter of the triangle is equal to the sum of the three sides of the triangle which are the height, base and hypotenuse. So,

Perimeter = height + base + hypotenuse = 84

We let x = height and y = base. We calculate area as follows:

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77 = x + 2y
x = 77 -2y

Hypotenuse is related to the other sides by the Pythagorean theorem.

Hypotenuse^2 = (x^2 + y^2)
(14 + x)^2 = x^2 + y^2
(14 + (77-2y))^2 = (77-2y)^2 + y^2
(91-2y)^2 = (77-2y)^2 + y^2

Solving for y and x
y = 28
x = 21

Area = (28)(21) / 2 = 294 square inches 
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factors ?

Step-by-step explanation:

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In words it would be said Thirty nine point four
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The difference of -2 to 14 is 16

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