The kind of wire and circuit breaker are: grounding wire such as fairly large bare copper wire.
<h3>What is the best wire for the above?</h3>
A 20A, 120V small-appliance branch circuit is known to be used in the case above.
Note that Electric range circuits needs about 50-amp, 240-volt made for circuit that is said to supplies the power to the range or oven via a 6-3 electrical wire.
Learn more about circuit breaker from
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I think it’s swipe up if i’m correct, if not sorry
Y=In(x)-5
hopefully it’s right :)
Answer:
a) AL will contains 0011 1100
Explanation:
In assembly language, shifting bits in registers is a common and important practice. One of the shifting operations is the SHR AL, x where the x specifies that the bits be shifted to the right by x places.
SHR AL, 2 therefore means that the bits contained in the AL should be shifted to the right by two (2) places.
For example, if the AL contains binary 1000 1111, the SHR AL, 2 operation will cause the following to happen
Original bit => | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 |
Shift once to the right => | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | (0) |
Shift once to the right => | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | (0) | (0) |
Notice;
(i) that there are two shifts - one at a time.
(ii) that the bits in bold face are the bits in the AL after the shift. Those that in regular face are those in the carry flag.
(iii) that the new bits added to the AL after a shift are the ones in bracket. They are always set to 0.
import java.util.Scanner;
public class MyClass1 {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
int smallest = 0, largest = 0, num, count = 0;
while (true){
System.out.println("Enter a number (-1 to quit): ");
num = scan.nextInt();
if (num == -1){
System.exit(0);
}
else if (num < 0){
System.out.println("Please enter a positive number!");
}
else{
if (num > largest){
largest = num;
}
if (num < smallest || count == 0){
smallest = num;
count++;
}
System.out.println("Smallest # so far: "+smallest);
System.out.println("Largest # so far: "+largest);
}
}
}
}
I hope this helps! If you have any other questions, I'll do my best to answer them.
