Answer:
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
F(x) 0.17 0.04 0.65 0.91 1
Step-by-step explanation:
Given that;
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
cumulative distribution function can be calculated by; be cumulatively up the value of p(x) with the values before it;
so
x F(x)
0 P(X = 0) = 0.17
1 P(X = 0) + P(X = 1) = 0.17 + 0.23 = 0.4
2 P(X = 0) + P(X = 1) + P(X = 2) = 0.17 + 0.23 + 0.27 = 0.65
3 P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.17 + 0.23 + 0.27 + 0.24 = 0.91
4 P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.17 + 0.23 + 0.27 + 0.24 + 0.09 = 1
Therefore, cumulative distribution function f(x) is;
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
F(x) 0.17 0.04 0.65 0.91 1
since the diameter of the base of the cylinder is 6 feet, then its radius is half that, or 3 feet.
![\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=9 \end{cases}\implies V=\pi (3)^2(9)\implies V=81\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%0AV%3D%5Cpi%20r%5E2%20h~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ar%3D3%5C%5C%0Ah%3D9%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Cpi%20%283%29%5E2%289%29%5Cimplies%20V%3D81%5Cpi)
I beleive 1 is C, and 2 is B!
8 centimeters would be your answer
