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2 years ago

Applications Day #1:

Mathematics

1 answer:

Lelu [443]2 years ago

6 0

I don’t even know how to get the information from the school that is not working on my

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Complete the equation of the line whose y-intercept is (0, -1) and slope is 4.<br> (Khan academy)

vagabundo [1.1K]

Answer:

y = 4x - 1

Step-by-step explanation:

y = mx + b

Here m is slope and b is y-intercept

m = 4; b = -1

y = 4x - 1

5 0

3 years ago

Nina owns a condominium where she paid $2,340 in maintenance fees this year. If her property taxes are 18% off this amount, how

Rufina [12.5K]

2340x0.18= 421.20

She paid $421.20 in property taxes

7 0

2 years ago

This last one I need help on too

ExtremeBDS [4]

Answer:

$x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}$

Step-by-step explanation:

simplify $\frac{-3}{x-2}$ by putting the negative sign on the outside. $\frac{2x}{x-1}-\frac{2x-5}{x^2-3x+2}=-\frac{3}{x-2}$

find the LCM of the denominators. It is (x-1)(x-2). Multiply by the LCM:

$\frac{2x}{x-1}\left(x-1\right)\left(x-2\right)-\frac{2x-5}{x^2-3x+2}\left(x-1\right)\left(x-2\right)=-\frac{3}{x-2}\left(x-1\right)\left(x-2\right)$

Simplify:

$2x\left(x-2\right)-\left(2x-5\right)=-3\left(x-1\right)$

solve: $x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}$

3 0

3 years ago

This is the result of solving an equation to find a value(s) for the variable(s) which make the equation true.

SOVA2 [1]

Answer:

Step 1: Simplify both sides of the equation.

8−2(3−x)=4x+6

8+(−2)(3)+(−2)(−x)=4x+6(Distribute)

8+−6+2x=4x+6

(2x)+(8+−6)=4x+6(Combine Like Terms)

2x+2=4x+6

Step 2: Subtract 4x from both sides.

2x+2−4x=4x+6−4x

−2x+2=6

Step 3: Subtract 2 from both sides.

−2x+2−2=6−2

−2x=4

Step 4: Divide both sides by -2.

−2x

−2

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Helppppppp pleaseee

Viktor [21]

Answer:

$x=2\sqrt{5}$

Step-by-step explanation:

If that is a square, then all sides are the same. Therefore, it's a $\sqrt{10}$ by $\sqrt{10}$ shape. We'll use Pythagorean Theorem to find the diagonal.

$a^2+b^2=c^2\\\sqrt{10}^2+ \sqrt{10}^2=x^2\\10+10=x^2\\20=x^2\\\sqrt{20}=x\\\sqrt{4*5}=x\\ 2\sqrt{5}=x$

Since it's not a fraction, there is no denominator to rationalize. Let me know if you have any other questions!

5 0

2 years ago