Answer:
Equation of curve = x2 + 16y2 + 16z2 = 16
Step-by-step explanation:
The steps and mathematical assumption and manipulation are shown in the attachment.
Applications Day #1:
1 answer:
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Answer:
a. Maximum= 27, minimum= -5
b. Maximum= 19, minimum=-37
Step-by-step explanation:
We have the function . Since the function correspond to a line, then the maximum and minimum values of the function over an interval are in the endpoints of the interval.
Observe that if the line has negative slope then the minimum value is in the right endpoint. If the line has positive slope the minimum value is in the left endpoint of the interval.
The function f(x) has slope m=8. Then
a. the minimum value of f(x) in the interval [0,4] is reach when x=0, and the minimum is and the maximum is
b. the minimum value of f(x) in the interval [-4,,3] is reach when x=-4, and the minimum is and the maximum is
Answer:
Given y-2x=4 →y=2x+4
Table of Solutions
xy = 2x + 4(x, y) * P * o * i * n * t
0 y = 2(0) + 4 = 4 (0,4)A(0,4)
2 y = 2(-2) + 4 = 0 (-2, 0) B(-2, 0)
1y = 2(1) + 4 = 6(1, 6) C(1, 6)
Plotting the points A, B and C on the graph paper and joint them to get the straight line BC as shown in graph sheet. This line is the required graph of the equation y - 2x = 4 .
(i) Plot the point (2, 8) on the graph paper. From the graph it is clear that the point (2, 8) lies on the line.
Checking algebraically: On substituting (2, 8) in the
given equation, we get LHS y-2x=8-2×2=8-4-4 RHS, So (2, 8) is a solution
(ii) Plot the point (4, 2) on the graph paper. You fin that (4, 2) does not lie on the line.
Checking algebraically: By substituting (4, 2) in the given equation we have
LHS =y-2x=2-2×4-2-8--6
=RHS, So (4, 2) is not a solution.
Step-by-step explanation:
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