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3 years ago

Solve the system of equations given below.

Mathematics

2 answers:

lbvjy [14]3 years ago

7 0

Answer:

Step-by-step explanation:

-5x = y - 5 (1)

-2y = -x - 21 (2)

Change x to the left hand side of equation (2)

x = 2y - 21 (3)

Multiply (1) by 2 times:

-10x = 2y - 10 (4)

Use (4) - (3)

-10x = 2y - 10

- x = 2y - 21

-11x = -10 + 21

-11 x = 11

x = -1

Apply x = -1 in (1)

-5*(-1) = y - 5

5 = y-5

y = 5+5

y = 10

So x = -1

y = 10

Hope this help you :3

Free_Kalibri [48]3 years ago

6 0

Hehe the answer is B (-1,10)

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PLS HELP ASAP

ale4655 [162]

Correct answer is : Area of triangle is $15\sqrt{3} sq.units$

Solution:-

We can do it in 2 methods.

Method 1:-

Given that AB=6, BC=10 and m∠B = 120

Then area of triangle = $\frac{1}{2}XbaseXheight$

Let us assume AB is base and D is an altitude from C onto AB.

Then sin(60)= $\frac{CD}{BC}$

CD = BC sin(60)

Hence height = $10*\frac{\sqrt{3}}{2}$ = $5\sqrt{3}$

Hence area of ΔABC = $\frac{1}{2} X6X5\sqrt{3} = 15\sqrt{3}$ sq.units

Method2:-

Area of triangle = $\frac{1}{2} acsin(B)$

Here a= BC=10, c=AB=6.

Hence area of triangle = $\frac{1}{2}X6X10sin(120) = 15\sqrt{3}$ sq.units

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2 years ago

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Answer:

Step-by-step explanation:

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