8,9,10,11,11,14,18,28,28,29,40,41,41,44,45,47,55 which histogram represents data
Elenna [48]
Answer:
did this b4
Step-by-step explanation:
I used bars of width 10. There are 3 values from 0-9; 4 values from 10-19; 3 values from 20-29; 0 values from 30-39; 6 values from 40-49; and 1 value from 50-59.
please mark as brainliest
<span>Population density is divided in to three forms that are physiological density, arithmetic density and agricultural density.
The number of people per unit area is the physiological density, it is also known as the real population density and total number of people divided by the total land area is arithmetic density population.
And if we compare both for India, The physiological density of India is greater than the arithmetic population density.</span>
Answer:
Step-by-step explanation:
18^y = 4/6 Take the log of both sides
log(18^y) = log(4/6)
log(18^y) = y * log(18)
log (4/6) = - 0.17609
y * log(18) = y * 1.25527
So
y = - 0.17609 / 1.25527
y = - 0.14056
Check
18^-0.14056 = 0.6661 which is close enough to 0.666666666
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z^4 = 8/5 Take the log of both sides.
log(z^4) = log(8/5) Simlplify the left. Take the log of the right.
4 * log(z) = 0.20416 Divide by 4
log(z) = 0.20416 /4
log(z) = 0.051029 Take the antilog of both sides.
z = 10^(0.051029)
z = 1.12467
Check
1.12467 ^ 4 = 1.6 which is what it should be.
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I can't really make out the third one.
The number it started with is -7
Answer:
No
Step-by-step explanation:
Say the price of 1 apple is x and the price of 1 orange is y. Then, we can write the two equations:
4x + 4y = 10
6x + 6y = 15
We can try to solve this by elimination, which means getting rid of one variable so that we're left with only 1 variable to solve for. Multiply the top equation by 3 and the bottom equation by 2:
3 * (4x + 4y) = 10 * 3 ⇒ 12x + 12y = 30
2 * (6x + 6y) = 15 * 2 ⇒ 12x + 12y = 30
Subtract the bottom equation from the top:
12x + 12y = 30
- 12x + 12y = 30
______________
0 + 0 = 0
Since we result in 0 = 0, that means any values of x and y we put into the equations will work, so we cannot find a unique price.
Hope this helps!
