Ask question

Ask question

All categories

Arte-miy333 [17]

3 years ago

9

A line of best fit....?

1 answer:

AlexFokin [52]3 years ago

3 0

I’m pretty sure the correct answer is C

You might be interested in

If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

5 0

3 years ago

IM IN DESPERATE NEEED!!!<br> What is the solution to this system of equations?

natta225 [31]

Answer:

$x + y - x = 6 - y - 4 \\ y = 2 - y \\ 2y = y \\ y = 1 \\ x + y = 6 \\ x + 1 = 6 \\ x = 5$

5 0

3 years ago

• Use whichever method you prefer (the area model or the distributive property)

kolbaska11 [484]

Answer: 2a^2+22a+−1

Step-by-step explanation:

Let's simplify step-by-step.

2a^2−5a+(9)(3)a−1

=2a^2+−5a+27a+−1

Combine Like Terms:

=2a^2+−5a+27a+−1

=(2a^2)+(−5a+27a)+(−1)

=2a^2+22a+−1

4 0

3 years ago

You are riding a roller coaster when a shoe falls off your foot. The function y=300−16t2 represents the height y (in feet) of th

Juli2301 [7.4K]

Answer:

Time to land on 11ft is 4.25 seconds

Step-by-step explanation:

Given

$y = 300 - 16t^2$

Required

Solve for t when height is 11ft

This implies that $y = 11$

So: substitute 11 for y in $y = 300 - 16t^2$

$11 = 300 - 16t^2$

Collect Like Terms

$16t^2 = 300 - 11$

$16t^2 = 289$

Express both sides as squares

$4^2 * t^2 = 17^2$

$(4t)^2 = 17^2$

Take square roots of both sides (ignore negative)

$4t = 17$

Solve for t

$t = \frac{17}{4}$

$t = 4.25$

Hence, time to land on 11ft is 4.25 seconds

8 0

3 years ago

What is 275 divide by 8

JulijaS [17]

The correct answer is 34.375. Hope this helps.

5 0

3 years ago

Read 2 more answers