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mina [271]
3 years ago
8

A ball is thrown from a height of 139 feet with an initial downward velocity of 15 ft/s. The ball's height h (in feet) after t s

econds is given by the following.
h=139-15t-16t^2

How long after the ball is thrown does it hit the ground?

Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

t = _______ seconds???
Mathematics
1 answer:
ella [17]3 years ago
6 0

Answer:

t = 2.52 seconds

Step-by-step explanation:

h=139-15t-16t^2

We want to know when the ball hits the ground

That would be when h=0

0 = 139-15t-16t^2

We can use the quadratic formula to find t

t = -b ± sqrt(b^2-4ac)

       ----------------------

          2a

where a = -16   b = -15  and c = 139

t = -(-15) ± sqrt((-15)^2-4(-16)139)

       ----------------------

          2(-16)

t = (15) ± sqrt(225+8896)

       ----------------------

          -32

t = (15) ± sqrt(9121)

       ----------------------

          -32

t = 15+ sqrt(9121)                       t = 15- sqrt(9121)

     --------------------   or                    -------------------  

           -32                                               -32

        -3.453247707        or              2.515747707

Since time cannot be negative

 2.515747707

Round to the nearest hundredth

t = 2.52 seconds

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For each system of equations, drag the true statement about its solution set to the box under the system?
natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

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y = 3x - 4

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One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

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- The system of equation has infinity many solutions if the

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* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

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∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

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Elena L [17]
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