70/196 = (14 x 5)/(14 x 14) = 5/14
Answer:
Option D, I agree with neither Elena nor Lin
Step-by-step explanation:
The remaining part of the question is attached herewith
Solution
As we can see in the image
ED is perpendicular to AB and BC is perpendicular to AB
Thus, as per the Pythagoras theorem,
AC^2 = AB^2 + BC^2
14^2 = 6^2 + BC^2
BC^2 = 196-36 = 160
BC = 12.649 OR 12.65
Hence, option D
I agree with neither Elena nor Lin
Step-by-step explanation:
![\text{Use:}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\left(\dfrac{1}{a}\right)^n\\\\=============================](https://tex.z-dn.net/?f=%5Ctext%7BUse%3A%7D%5C%5C%5C%5Ca%5En%5Ccdot%20a%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%5Cdfrac%7Ba%5En%7D%7Ba%5Em%7D%3Da%5E%7Bn-m%7D%5C%5C%5C%5C%28a%5En%29%5Em%3Da%5E%7Bnm%7D%5C%5C%5C%5Ca%5E%7B-n%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7Ba%7D%5Cright%29%5En%5C%5C%5C%5C%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D)
![A.\ \dfrac{5^3}{5^6}=5^{3-6}=5^{-3}=\left(\dfrac{1}{5}\right)^3\\\\B.\ (14^3)^6=14^{3\cdot6}=14^{18}\\\\C.\ 8^3\cdot8^6=8^{3+6}=8^9\\\\D.\ \dfrac{16^6}{16^3}=16^{6-3}=16^3\\\\E.\ (21^3)^{-6}=21^{3\cdot(-6)}=21^{-18}=\left(\dfrac{1}{21}\right)^{18}\\\\F.\ 100^0=1\\\\G.\ \dfrac{\left(\frac{2}{5}\right)^8}{\left(\frac{2}{5}\right)^6}=\left(\dfrac{2}{5}\right)^{8-6}=\left(\dfrac{2}{5}\right)^2\\\\H.\ (0.15)^{-2}\cdot(0.15)^4=(0.15)^{-2+4}=(0.15)^2\\\\I.\ 7^{-5}=\left(\dfrac{1}{7}\right)^5](https://tex.z-dn.net/?f=A.%5C%20%5Cdfrac%7B5%5E3%7D%7B5%5E6%7D%3D5%5E%7B3-6%7D%3D5%5E%7B-3%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7B5%7D%5Cright%29%5E3%5C%5C%5C%5CB.%5C%20%2814%5E3%29%5E6%3D14%5E%7B3%5Ccdot6%7D%3D14%5E%7B18%7D%5C%5C%5C%5CC.%5C%208%5E3%5Ccdot8%5E6%3D8%5E%7B3%2B6%7D%3D8%5E9%5C%5C%5C%5CD.%5C%20%5Cdfrac%7B16%5E6%7D%7B16%5E3%7D%3D16%5E%7B6-3%7D%3D16%5E3%5C%5C%5C%5CE.%5C%20%2821%5E3%29%5E%7B-6%7D%3D21%5E%7B3%5Ccdot%28-6%29%7D%3D21%5E%7B-18%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7B21%7D%5Cright%29%5E%7B18%7D%5C%5C%5C%5CF.%5C%20100%5E0%3D1%5C%5C%5C%5CG.%5C%20%5Cdfrac%7B%5Cleft%28%5Cfrac%7B2%7D%7B5%7D%5Cright%29%5E8%7D%7B%5Cleft%28%5Cfrac%7B2%7D%7B5%7D%5Cright%29%5E6%7D%3D%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%29%5E%7B8-6%7D%3D%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%29%5E2%5C%5C%5C%5CH.%5C%20%280.15%29%5E%7B-2%7D%5Ccdot%280.15%29%5E4%3D%280.15%29%5E%7B-2%2B4%7D%3D%280.15%29%5E2%5C%5C%5C%5CI.%5C%207%5E%7B-5%7D%3D%5Cleft%28%5Cdfrac%7B1%7D%7B7%7D%5Cright%29%5E5)
![J.\ 4\cdot4^3=4^{1+3}=4^4](https://tex.z-dn.net/?f=J.%5C%204%5Ccdot4%5E3%3D4%5E%7B1%2B3%7D%3D4%5E4)
Next step: Applying distributive property
<h2>
Explanation:</h2><h2>
</h2>
__________________________________
<em>The correct question is the following:</em>
<em />
<em>Julie started solving the equation 3x=4+2(3−x). which is a correct next step?</em>
__________________________________
Step 1. Apply distributive property:
![3x=4+2(3-x) \\ \\ 3x=4+6-2x](https://tex.z-dn.net/?f=3x%3D4%2B2%283-x%29%20%5C%5C%20%5C%5C%203x%3D4%2B6-2x)
Step 2. Add 4 and 6
![3x=4+6-2x \\ \\ 3x=10-2x](https://tex.z-dn.net/?f=3x%3D4%2B6-2x%20%5C%5C%20%5C%5C%203x%3D10-2x)
Step 3. Add 2x to both sides
![3x+2x=10-2x+2x \\ \\ 5x=10](https://tex.z-dn.net/?f=3x%2B2x%3D10-2x%2B2x%20%5C%5C%20%5C%5C%205x%3D10)
Step 4. Divide both sides by 5
![\frac{5x}{5}=\frac{10}{5} \\ \\ x=2](https://tex.z-dn.net/?f=%5Cfrac%7B5x%7D%7B5%7D%3D%5Cfrac%7B10%7D%7B5%7D%20%5C%5C%20%5C%5C%20x%3D2)
<h2>Learn more:</h2>
Distributive property: brainly.com/question/10794694
#LearnWithBrainly
X=11
-5(x+1) = -3(2x-2)
distribute
-5x-5= -6x+6
both +6x
x-5=6
plus 5 on both
x=11