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vodka [1.7K]
3 years ago
9

A worker can complete the assembly of 15 cell phones in 6hrs. At this rate, how many can the worker complete in a 40hrs work wee

k?? With full workin!!​
Mathematics
1 answer:
vitfil [10]3 years ago
4 0

Answer: 100 cell phones.

Step-by-step explanation:

The worker makes 2.5 phones an hour. 2.5 x 40 = 100.

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QUESTION 1
lukranit [14]
1.) 2368000 (two million, three hundred sixty-eight thousand)
2.) 864,346,000 rounded to nearest thousand
3.) 864,345,537.00 not 100% on the last answer

Good luck
8 0
3 years ago
A circle has a diameter of 24 units. Find the circumference and area of the circle in terms of π.
enyata [817]
Circumference=24 pi
Area=144 pi, shown clearly in photo

7 0
3 years ago
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What am I supposed to do hear im confused
natulia [17]

Answer:

Step-by-step explanation:

In No.1

First you find the total number of girls which is 56-20 =36 girls in total

So to get number of boys who watched tennis 20-13=7 boys watched tennis

To get number of girls who didnt watch you do 36-17=19 girls who watched

Then add o get the totals

No.2

First you get the total number of male 80-47=33 males

Next you find the number of females doing phyisics 33-19=14 females

Next you find the number of females doing chemistry by 47-(18 + 14)=15 females

To get the number of males diong chemistry 21-15=6 males

Number of males doing biology 33-(19+6)=8

Then find the remaining totals

2

No. 2 (b)

Because there is a high number of students doing physics and most of them are female

7 0
4 years ago
Read 2 more answers
Please help me and If your answer is wrong or not appropreat I will report it
arsen [322]

Answer:

972 x^16 y^24

Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

Multiply each exponent in -2 x^3 y^7 by 2:

(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

2×7 = 14:

(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5

2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

5×2 = 10:

4×3^5 x^6 y^14 x^(5×2) y^10

5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

3^5 = 3×3^4 = 3 (3^2)^2:

4×3 (3^2)^2 x^6 y^14 x^10 y^10

3^2 = 9:

4×3×9^2 x^6 y^14 x^10 y^10

9^2 = 81:

4×3×81 x^6 y^14 x^10 y^10

3×81 = 243:

4×243 x^6 y^14 x^10 y^10

4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:

4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

4×243 x^(6 + 10) y^24

6 + 10 = 16:

4×243 x^16 y^24

4×243 = 972:

Answer: 972 x^16 y^24

8 0
2 years ago
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Write as an addition problem: 83 -136
Arada [10]

Answer:

83+136

Step-by-step explanation:

4 0
3 years ago
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