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3 years ago

write a story problem that can be solved by finding the sum of 506,211 and 424,809.then solve the problem

2 answers:

6 0

Jordan had 506,211 pairs of nike shoes then she bought 424,809 more. Jordan wants to find out how many pairs of nike shoes he has what is the answer Jordan is looking for? Answer: 931,020 pairs of nike shoes

Aleks04 [339]3 years ago

4 0

There are 2 people mike and joe mike worked for 506,211 min. And joe worked 424,809 min.how much more did mike work then joe?

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sandra and her friend went to the candy store. each of them purchased a bag of jelly beans. sandra's bag weighed 1.25 pounds. He

Nuetrik [128]

You would subtract.

The question is asking who has more, so to find out, you need to take away the smaller amount from the bigger amount. (1.25-1.05)

So Sandra bought more candy. Hope this helps!

3 0

3 years ago

Read 2 more answers

Please help please please help

arsen [322]

46.19 should be the answer

4 0

3 years ago

Solve this PLZ! 4 - 7 (v - 9) = -7 -6(v - 10)

Arisa [49]

I maybe wrong, but I think it is 14

Simplify both sides of the equation
(Do distributive property)
Add 6v to both sides
Subtract 67 from both sides
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7 0

3 years ago

Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

Artist 52 [7]

X^3 - 21x = -20add 20 to both sidesx^3 - 21 x + 20 = 0Rational Root Theorem:Factors of P (constant) 20 = 1, 2, 4, 5, 10, 20------------------------------- Factors of Q (leading Coefficient) = 1
Possible zeros (all + -) 1/1, 2/1, 4/1, 5/1, 10/1, 20/1
Of the choices given only the number 1 is a possible root.

4 0

4 years ago

Read 2 more answers

How do i solve that question?

yawa3891 [41]

a) The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ .

b) The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ .

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ .

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable ( $y, t$ ) in each side of the identity:

$6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t$ (1)

$6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C$

Where $C$ is the integration constant.

By table of integrals we find the solution for each integral:

$-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C$

If we know that $x = 0$ and $y = 1$ , then the integration constant is $C = -2$ .

The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ . $\blacksquare$

b) In this case we need to solve a first order ordinary differential equation of the following form:

$\frac{dy}{dx} + p(x) \cdot y = q(x)$ (2)

Where:

$p(x)$ - Integrating factor
$q(x)$ - Particular function

Hence, the ordinary differential equation is equivalent to this form:

$\frac{dy}{dx} -\frac{1}{x}\cdot y = x^{2}+\frac{1}{x}$ (3)

The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ . $\blacksquare$

The solution for (2) is presented below:

$y = e^{-\int {p(x)} \, dx }\cdot \int {e^{\int {p(x)} \, dx }}\cdot q(x) \, dx + C$ (4)

Where $C$ is the integration constant.

If we know that $p(x) = -\frac{1}{x}$ and $q(x) = x^{2} + \frac{1}{x}$ , then the solution of the ordinary differential equation is:

$y = x \int {x^{-1}\cdot \left(x^{2}+\frac{1}{x} \right)} \, dx + C$

$y = x\int {x} \, dx + x\int\, dx + C$

$y = \frac{x^{3}}{2}+x^{2}+C$

If we know that $x = 1$ and $y = -1$ , then the particular solution is:

$y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ . $\blacksquare$

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

3 0

3 years ago