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Nataliya [291]
3 years ago
9

If you was born five years ago how old would u be

Mathematics
2 answers:
Burka [1]3 years ago
7 0
5 years old. You were alive and out of another human for 5 years which makes you five years old. 
max2010maxim [7]3 years ago
3 0
I was born in 2003 an I’m 14 since my birthday passed so I would be 9
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The amount of gas that a helicopter uses is directly proportional to the number of hours spent flying. the helicopter flies for
Anna007 [38]
3232 gallons of fuel are used up

7 0
3 years ago
Read 2 more answers
A shipment To a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 ar
riadik2000 [5.3K]

Answer:

<u>630</u> MP3 players are likely to be defective.

Step-by-step explanation:

Given:

A shipment to a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 are defective.

Now, to find the MP3 players which are likely to be defective.

Let the defective MP3 players be x.

Total MP3 players = 4500.

In sample of 50 MP3 players 7 are defective.

Now, setting the proportion:

If, 50 is equivalent to 7.

Then, 4500 is equivalent to x.

Now, to solve using cross multiplication method:

\frac{50}{7} =\frac{4500}{x}

<em>By cross multiplying we get:</em>

<em />50x=31500<em />

<em>Dividing both sides by 50 we get:</em>

x=630.

Therefore, 630 MP3 players are likely to be defective.

5 0
3 years ago
Where do I put the other two
Ilya [14]
You can put h on -1 and sum on 0.4. Also, you put 1.4 in the wrong place. It should be three more places to the right.
4 0
3 years ago
Pls can someone help me<br><img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7
Firlakuza [10]

Answer:

= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )

Step-by-step explanation:

Given the expression log10\sqrt{36} + log10\sqrt{2}  - log10\sqrt{7} \\

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

log10\sqrt{36} + log10\sqrt{2}  - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )

6 0
3 years ago
I need help!! I'll report if wrong ​
ss7ja [257]

Answer:

23

Step-by-step explanation:

2+2+3+4+5+6 = 23

3 0
3 years ago
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