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Arturiano [62]
2 years ago
9

True or False

Mathematics
1 answer:
matrenka [14]2 years ago
8 0

Answer:

for saken it is better to use ordinary calculator than cp because they have a big difference. That's all I can say

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Will give medal to best answer!
mart [117]
We have two sides and one angle opposite to one of the known sides.

Begin with applying the Law of Sines to find angle A:
\frac{sin A }{a} = <span>\frac{sin C }{c}

Then, solve for sin A:
</span>sin A = \frac{a sinC}{c}

Now, plug in numbers:
sin A = 19 × sin(38) / 10 = 1.17

We know that it does not exist an angle whose sin is bigger than 1, therefore
no triangle is formed.

6 0
3 years ago
What is Something divided by something equals 140
inn [45]
Answers my vary but what i got is 140 divided by 10 = 14
4 0
3 years ago
Read 2 more answers
To mix the color “autumn purple,” a painter mixes 28 parts of blue to 48 parts of red. What is the ratio of blue to red? Express
kupik [55]

Answer:

blue : red

7      : 12

Step-by-step explanation:

blue : red

28      48

Divide each by 4

28/4   48/4

7         12


blue : red

7      : 12

7 0
3 years ago
Read 2 more answers
Solve for the literal equation for z: 3z-s=r
Vikentia [17]

Answer:

i think it is. r = -s + 3z could be wrong sorry if it is

8 0
3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
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