Answer:
Bet
Step-by-step explanation:
Answer:
4Joules
Step-by-step explanation:
According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,
F = ke where
F is the applied force
K is the elastic constant
e is the extension
If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'
can be gotten using k = f/e where
F = 6N, e = 3m
K = 6N/3m
K = 2N/m
Work done on an elastic string is calculated using 1/2ke².
If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;
1/2× 2× (2)²
= 4Joules
The answer to this question is C
Because you are supposed to do division first following PEMDAS so 12÷2=6 then you would do 2+6=8 SO THE ANSWER IS C
7P3= 7!/(7-3)!
= 7!/4!
= 7*6*5
= 210
C.210
We have the following curve:
So we need to find <span>an equation of the
tangent line to this curve at the point
. So let's find out if this point, in fact, belongs to the curve:
</span>
.
<span>
We also know that:
</span>
<span>
Given that the point is:
</span>
Then we will say that:
Therefore:
Computing the derivative:
So the derivative solved for
is in fact the
slope of the line at the point
, then:
Finally, the tangent line is:
<em>This is shown in the figure below.</em><span>
</span>