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Naddika [18.5K]
3 years ago
6

What is the maximum number of y-intercepts a line can have? I will mark brainliest!

Mathematics
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

one

Step-by-step explanation:

The maximum number of y intercepts a line can have is one

A line can only cross the y axis one time

A line can only cross the x axis one time

Otherwise it is not linear

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Help me please. I don’t understand this math. My math teacher is mean. :(((((
Verdich [7]

Answer:

The height of the given rectangular prism is 5cm.

Step-by-step explanation:

Given that the volume of the rectangular prism is 5cm^3

And length is \frac{3}{4} and width is 1\frac{1}{3}

That is V=5cm^3[/tex] , l=\frac{3}{4}cm and w=1\frac{1}{3}cm

We have the  volume of the rectangular prism V=lwh cubic centimeter

V=lwhcm^3

Substituting the values in above formula

5=\frac{3}{4}\times 1\frac{1}{3}\times h

5=\frac{3}{4}\times \frac{4}{3}\times h

5=1\times h

5=h

Rewritting as below

h=5cm

Therefore the height is 5cm

5 0
3 years ago
Read 2 more answers
he data represents the daily rainfall​ (in inches) for one month. Construct a frequency distribution beginning with a lower clas
Licemer1 [7]

Answer:

It is not normally distributed as it has it main concentration in only one side.

Step-by-step explanation:

So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).

So, let us begin the groupings into their different classes, shall we?

Data given:

0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.

(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.

(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31

(3). 0.4 - 0.6 : there are 2 values that falls into this category.

(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.

Class interval            frequency.

0.00 - 0.20.                   15.

0.20 - 0.40.                    2.

0.4 - 0.6.                        2.

4 0
3 years ago
Suppose in the population, the Anger-Out score for men is two points higher than it is for women. The population variances for m
tatuchka [14]

Answer:

a)= 2

b) 6.324

c) P= 0.1217

Step-by-step explanation:

a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)

b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by

σ_X`1- X`2 = √σ²/n1 +σ²/n2

Var ( X`1- X`2) = Var X`1 + Var X`2 =  σ²/n1 +σ²/n2

so

σ_X`1- X`2 =√20 +20 = 6.324

if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.

Where as Z is normally distributed with mean zero and unit variance.

If we take X`1- X`2= 0 and u1-u2= 2  and standard deviation of the sampling distribution = 6.324 then

Z= 0-2/ 6.342= -0.31625

P(-0.31625<z<0)= 0.1217

The probability would be 0.1217

8 0
2 years ago
2. The amount of sap that is collected from
Burka [1]
Population: six sugar maples
Sample: sap
7 0
3 years ago
Thirty-six and fifty-two thousandths as a decimal number
dimaraw [331]
In decimal form that would be 36.052
5 0
3 years ago
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