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Brums [2.3K]
3 years ago
8

A spring 1.7 m long with force constant 550 N/m is hung from the ceiling of an elevator, and a block of mass 15 kg is attached t

o the bottom of the spring. (a) By how much is the spring stretched when the block is slowly lowered to its equilibrium point
Physics
1 answer:
Nastasia [14]3 years ago
3 0

Answer:

27 cm

Explanation:

ASSUMING the elevator is in a constant velocity state (could be zero)

mg = kx

x = mg/k = 15(9.8)/550 = 0.267272... m ≈ 27 cm

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Explanation:

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valentina_108 [34]

Answer:

12.3 m/s

Explanation:

The Doppler equation describes how sound frequency depends on relative velocities:

fr = fs (c + vr)/(c + vs),

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c is the speed of sound,

vr is the velocity of the receiver,

and vs is the velocity of the source.

Note: vr is positive if the receiver is moving towards the source, negative if away.

Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.

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5 0
3 years ago
On a trolley ride around an amusement park, a child travelled from one signpost to a second signpost at a constant speed of 125
Tomtit [17]

Answer:

Explanation:

Speed given = 125 m /min

125 /60 m /s

In 450 second it will travel

= 450 x 125 / 60

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As the distance  is covered in less than 450 seconds , The distance must be less than 937.5 m

In 400 seconds , it will travel

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833.33 m

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20 - 50 = 15a

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a = -30 / 15

a = -2 m/s²
6 0
4 years ago
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