Question

A 55-liter tank is full and contains 40kg of fuel. Find using Sl units: • Density p. • Specific Weight y • Specific Gravity Answer tolerance = 1%. Be sure to include units. The sign of the answers will not be graded, use a positive value for your answer. Your answers: p= (Enter a positive value) y = (Enter a positive value) SG = (Enter a positive value)

Answer 1

Answer:

p = 727.273 kg/m3,  y = 7134.545 N/m^3, SG = 0.7273

Explanation:

Density is simply the amount of mass of a substance per unit of volume. It can be found by dividing the mass in kg by the volume im m^3:

$p = \frac{m}{v} = \frac{40kg}{55lt*\frac{1 m^3}{1000 lt}} = 727.273 kg/m^3$

Specific weight is the weight of the substance per unit of volume. The weight is the mass of the material times the gravity, and it represents the force that the earth exerts on an object. Another way of calculate this value, its multiplying the density of the fuel times the gravity. Then:

$y = p*g = 727.273 kg/m^3 * 9.81 m/s^2 = 7134.545 N/m^3$

Specific Gravity is the ratio of the density of the substance to the density of a reference substance. For liquids, the reference substance is water at 4°C, which has a density of about 1000 kg/m^3.

$SG =\frac{ p_{fuel}}{p_{water}} = \frac{727.273 kg/m^3}{1000 kg/m^3} = 0.7273$