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4 years ago

What is the reversal experienced by an image formed in a plane mirror called?

Physics

1 answer:

Lerok [7]4 years ago

4 0

Answer:

Lateral inversion

Explanation:

When an object is placed in front of a plane mirror, the appearance of the object on the plane mirror appears as a reversal of the object. This effect is known as lateral inversion.

Lateral inversion occurs as a result of the fact that light is reflected by a plane mirror. The image formed by the plane mirror is as far behind the mirror as the object is in front of it. Hence lateral inversion occurs because of the way our brains perceive images on a plane mirror. The mirror image of symmetrical letters and objects do not show lateral inversion.

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Answer:

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3 years ago

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What does a force moving an object through a distance transfer? A. sound B. energy C. weight D. mass

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3 years ago

A dragster completed a 402.3-(0.2500-mi) run in 5.023s. If the car had a constant acceleration, what was its acceleration and fi

Ray Of Light [21]

Answer:

v = 80.092 m/s

a = 15.945 m/s²

Explanation:

Given,

The distance completed by the dragster, d = 402.3 m

The time taken by the dragster to complete that distance is, t = 5.023 s

The initial velocity of the dragster, u = 0

The final velocity of the dragster, v = ?

The acceleration of the dragster, a = ?

The velocity of the body is given by the formula

v = d/t m/s

Substituting the above values inn the equation

v = 402.3 m / 5.023 s

= 80.092 m/s

So, the velocity of the dragster is, v = 80.092 m/s

The acceleration of the body is given by the formula

a = (v - u)/t m/s²

Substituting the above values in the equation

= (80.092 - 0) / 5.023

= 15.945 m/s²

Hence, the acceleration of the dragster is, a = 15.945 m/s²

6 0

3 years ago

A tiger leaps with a horizontal speed of 4.5 m/s from a boulder and lands 15 meters away.What is the vertical velocity with whic

Gelneren [198K]

Answer:

v_oy = 16.33 m/s

Explanation:

To find the vertical velocity of the tiger, you use the information about the horizontal velocity and maximum horizontal distance traveled.

You use the following formula for the range of the trajectory:

$x_{max}=\frac{2v_{ox}v_{oy}}{g}$ ( 1 )

v_ox: horizontal initial velocity = 4.5m/s

v_oy: vertical initial velocity = ?

g: gravitational acceleration = 9.8m/s^2

x_max: range of the trajectory = 15 m

You do v_oy the subject of the formula ( 1 ) and you replace the values of the other parameters in order to calculate v_oy:

$v_{oy}=\frac{gx_{max}}{2v_{ox}}=\frac{(9.8m/s^2)(15m)}{2(4.5m/s)}\\\\v_{oy}=16.33\frac{m}{s}$

hence, the initial vertical velocity of the tiger is 16.33m/s

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3 years ago