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diamong [38]
2 years ago
14

Q|C Review. A particle of mass 4.00kg is attached to a spring with a force constant of 100 N/m . It is oscillating on a friction

less, horizontal surface with an amplitude of 2.00m . A 6.00 - kg object is dropped vertically on top of the 4.00-kg object as it passes through its equilibrium point. The two objects stick together.(d) Account for the change in energy.
Physics
1 answer:
Nezavi [6.7K]2 years ago
8 0

The change in energy after the collision is <u>0.5</u>

<u />

<h3>What is change in energy?</h3>

This refers to the difference in the energy where energy is the capacity to do work.  There different forms of energy they include mechanical energy, solar energy, electrical energy and so on.

The energy described in the problem is mechanical energy and it is of two types kinetic energy and potential energy

<h3>solving for the change in energy as a result of the collision</h3>

where mass of particle mp = 4 kg

mass of object mb = 6 kg

force constant of spring k = 100 N/m

amplitude A = 2 m

kinetic energy = 1/2 mv^2

initial velocity u = Aω

ω = sqrt ( 100/ 4 )

u = 2 sqrt ( 100/ 4 )

u = 10m/s

final velocity v = 5 m/s

change in energy

= - 0.5 * ( 4 + 4 ) * 5^2 + 0.5 * 4 * 10^2 ) / 0.5 * 4 * 10^2

= 0.5

Read more on change in energy here: brainly.com/question/26066414

#SPJ4

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