Answer: 272
Step-by-step explanation:
Let a1=11
a2=20
a3=29
Formula for sequence=
an=a1+(n-1)d
an = nth term
a1= first term
n= nth position
d= common difference
We are looking for the 30th term,so our n=30
d= a2-a1
d= 20-11
d= 9
Using the formula
an= a1+(n-1)d
a30= 11+(30-1)9
a30= 11+(29)9
a30= 11+(29×9)
a30= 11+261
a30= 272
Therefore, the 30th term is 272
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
Answer:
12.12%
Step-by-step explanation:
We have that the formula is given by:
A = p * e ^ (r * t)
From here, we know that A = 200000; p = 20000 and the time we can calculate 40 - 21 = 19
if we replace we have:
200000 = 20000 * e ^ (19 * r)
we must calculate r:
e ^ (19 * r) = 200000/20000
e ^ (19 * r) = 10
19 * r = ln 10
r = ln 10/19
r = 0.1212
In other words, the rate of growth is 12.12%
Answer:
1,757,600,000
Step-by-step explanation:
company consists of 3 letters followed by 5 numbers how many different account numbers are possible if repetitions of letters and digits are allowed.
We have 26 lettrs and 10 digits
So, the possible out comes for each one of the letters = 26
And the possible out comes for each one of the numbers = 10
∵ repetitions of letters and digits are allowed.
So, the possible accounts are = 26³ * 10⁵ = <u>1,757,600,000</u>
Answer: 2527 divided by 8 equals
315 with a remainder of 7
Step-by-step explanation:
