Question

The initial temperature of a bomb calorimeter is 28.50°C. When a chemist carries out a reaction in this calorimeter, its temperature decreases to 27.45°C. If the calorimeter has a mass of 1.400 kg and a specific heat of 3.52 J/(gi°C), how much heat is absorbed by the reaction? Use mc020-1.jpg. 140 J 418 J 1,470 J 5,170 J

Answer 1

Answer is: 5,170 J of heat is absorbed by the reaction.

ΔT= 28.50°C - 27.45°C = 1.05°C; temperature change.

m = 1400 g; mass of substance.

cp= 3.52 J/g·°C, specific heat capacity of the substance.

Q = m(granite) · ΔT(granite) · cp(granite).

Q = 1400 g · 1.05°C · 3.52 J/g·°C.

Q = 5,170 J; amount of energy gained.

Answer 2

It's D. the last option.

Hope this help's!!!!!!!!!!