Answer:
reaction rates increase because reactants move faster, collide more often, and produce more collisions with the required energy of activation.
Explanation:
<em>A</em><em>t</em><em> </em><em>h</em><em>i</em><em>g</em><em>h</em><em>e</em><em>r</em><em> </em><em>t</em><em>e</em><em>m</em><em>p</em><em>e</em><em>r</em><em>a</em><em>t</em><em>u</em><em>r</em><em>e</em><em>s</em><em>,</em><em> </em>the reactant atoms gain high kinetic energy which decreases the intermolecular forces of attraction between these atoms/molecules.
Hence the rate of collision is very high which decreases the activation energy and products are formed with in a short period of time.
The concentration of the bromine solution, given the data is 0.04 M
<h3>What is molarity? </h3>
Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the mole of bromine molecule (B₂)</h3>
- Mass of B₂ = 1.6 g
- Molar mass of bromine molecule (B₂) = 80 × 2 = 160 g/mol
- Mole of bromine molecule (B₂) = ?
Mole = mass / molar mass
Mole of bromine molecule (B₂) = 1.6 / 160
Mole of bromine molecule (B₂) = 0.01 mole
<h3>How to determine the molarity of the bromine solution</h3>
- Mole of bromine molecule (B₂) = 0.01 mole
- Volume of solution = 250 cm³ = 250 / 1000 = 0.25 L
- Molarity bromine solution =?
Molarity = mole / Volume
Molarity bromine solution = 0.01 / 0.25
Molarity bromine solution = 0.04 M
Thus, molarity of the bromine solution is 0.04 M
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Answer:
2.5litres
0.0005moles
0.56M
0.75M
0.1369M
0.255moles
0.0163M
0.10625M
3.312g
1221.14cm³
Explanations
1. 25÷1000=2.5l
2.Moles=Mass÷RFM
50÷1000÷(100)
0.0005moles
3.I litre=1000cm³
0.75litres=?
750cm³
0.42moles=750cm³
?=1000cm³
0.56M
4. Molarity=Conc. in g/l÷RFM
Conc.g/l
15g=500cm³
1000cm³
30g/l
Molarity
30÷(23+16+1)
0.75M
5.4.6g=250cm³
1000cm³
18.4g/l
Molarity
18.4÷(134.446)
0.1369M
6.3moles=1000cm³
(0.085×1000)
0.255moles
7.Conc.g/l
37.5cm³=0.181g
1000cm³
4.827g/l
Molarity=4.827÷(296)
0.0163M
Element C will have 5 protons
When we say STP that means the system is at its standard temperature and pressure. Both systems is having the same condition hence temperature and pressure is constant. We then set the amount of gas in both cases to be equal. Hence from the ideal gas law,
PV=nRT we can say that with everything constant, volume must also be constant.
The answer is (2) 2 L of methane gas.