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kicyunya [14]
3 years ago
14

A sample of sandstone consists of only silica (SiO2) and calcite (CaCO3). When sandstone is heated, calcium carbonate decomposes

to calcium oxide and carbon dioxide. Silica does not decompose. A 18.7 mg sample of the sandstone rock yields 3.95 mg of carbon dioxide.i) What is the mass of calcium carbonate in the sandstone rock in milligrams?ii) What is the percent of calcium carbonate in the sandstone rock?iii) What is the percentage of silica in sandstone rock?
Chemistry
1 answer:
anzhelika [568]3 years ago
5 0

Answer:

0

Explanation:

To calculate, the mass of Carbondioxide is 3.45mg

Then the decomposition of Carbondioxide gives 0 on calculation

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Examine the chemical equation Al + O2 Al2O3
AURORKA [14]
I think it is aluminum oxide

5 0
3 years ago
I set up the conversion factor as 1 mol H20 / 18.02 g H2O because?
Andrej [43]

Answer:

How many grams of H2O are in 1.0 mole of H2O?

18.02 grams

The average mass of one H2O molecule is 18.02 amu. The number of atoms is an exact number, the number of mole is an exact number; they do not affect the number of significant figures. The average mass of one mole of H2O is 18.02 grams.

#Yourchuu

8 0
3 years ago
4. How many moles of gold (Au) are in a pure gold nugget having a mass of 25.0 grams.
ikadub [295]
<h3>Answer:</h3>

0.127 mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 25.0 g Au

[Solve] moles Au

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 25.0 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
  2. [DA] Multiply/Divide [Cancel out units:                                                          \displaystyle 0.126923 \ mol \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.126923 mol Au ≈ 0.127 mol Au

3 0
3 years ago
Read 2 more answers
Name some acids and in what and how we used them
Ne4ueva [31]

Answer:

Acid Uses

Organic acids

Citric acid As a preservative for food As a flavouring agent

Ascorbic acid (also called vitamin C) In the treatment of bone marrow and scurvy diseases

Acetic acid Added to pickles to make them sour

Explanation:

7 0
3 years ago
Even though the molecular formula of acetylene is C2H2, and that of benzene is C6H6, these compounds have the same percent compo
alexandr402 [8]

Answer:

CH

Explanation:

The empirical formular is the simplest formular of a compound. It shows the relative number of elements present in a compounds. It shows the number of atoms of elements present in simple ratios.

In both compounds, the ratio of the carbon to hydrogen s 1:1

In C2H2;

C : H = 2 : 2 (Which is equivalent to 1 : 1)

In C6H6;

C : H = 6 : 6 (Which is equivalent to 1 : 1)

This means the empirical formular is CH

7 0
3 years ago
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