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BaLLatris [955]
3 years ago
11

Fredric leads a team of hikers for a full-day hike. The total elevation gain during the hike is 2,100 feet. All of the hikers ha

ve to pass two checkpoints before they reach the peak. The elevation gain from the starting point to checkpoint 1 is 100 feet less than double the elevation gain from checkpoint 2 to the peak. The elevation gain from checkpoint 1 to checkpoint 2 is the mean of the elevation gain from the start to checkpoint 1 and the elevation gain from checkpoint 2 to the peak. Let x represent the elevation gain from the starting point to checkpoint 1, y represent the elevation gain from checkpoint 1 to checkpoint 2, and z represent the elevation gain from checkpoint 2 to the peak. Which augmented matrices represent the context of this scenario?
Mathematics
1 answer:
andrezito [222]3 years ago
5 0
So you can solve this by drawing a digram. Draw each points and label all checkpoints. Study the drawing as long as you can to understand the situation. The question is asking for too much, so its a slippery slope.
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A scuba diver dove from the surface of the ocean to an elevation of -79 9/10 feet at a rate of -21.3 per minute. After spending
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The rate of change of the divers elevation is approximately 24.71 feet/minute

Step-by-step explanation:

The given information are;

The depth to which the scuba diver dove =-79\frac{9}{10} \ feet

The rate at which he dove = -21.3 feet/minute

The time which he spent at that elevation = 10.5 minutes

The elevation the diver then ascended to = -8\frac{9}{10} \ feet

The total time for the dive = 17\frac{1}{8} \ minutes

Therefore, the time, t_d, with which the scuba diver descended to -79\frac{9}{10} \ feet is given as follows;

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The time, t_e, it took the scuba diver to elevate to -8\frac{9}{10} \ feet is given as follows;

t_e = 17\frac{1}{8} \ minutes - (3.75 + 10.5) minutes ≈ 2.8738 minutes

The rate of change of the divers elevation = (Final elevation - Initial elevation)/(Time taken)

∴ The rate of change of the divers elevation = (-8\frac{9}{10} \ feet - (-79\frac{9}{10} \ feet ))/(2.87 minutes) = 71/2.8738 ≈ 24.71 feet/minute to the nearest hundredth

The rate of change of the divers elevation ≈ 24.71 feet/minute.

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