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2 years ago

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Mathematics

1 answer:

Vlad [161]2 years ago

6 0

Answer:

Step-by-step explanation:

V=1/3Bh

v=1/3s^2 (1/2s)

v=1/6s^2

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Please answer it now in two minutes

o-na [289]

Answer:

p = 3

Step-by-step explanation:

This is an isosceles right triangle

=> 2side^2 = (hypotenuse)^2

=> 2p^2 = (3sqrt(2))^2

=> 2p^2 = 18

=> p^2 = 9

=> p = 3

5 0

3 years ago

7 Raja is laying tiles on a path that forms

ser-zykov [4K]

Answer:

The perimeter of the garden is 400 feet.

Step-by-step explanation:

Consider the provided information,

Raja is laying tiles on a path that forms the diagonal of a square garden. If Raja is told that the length of the diagonal path is $100\sqrt{2}$

The length of the diagonal of a square garden is $100\sqrt{2}$

Let x represent the side of square.

By Pythagorean theorem we know: $a^2+b^2=c^2$

Where c is hypotenuse.

The diagonal of the square divides the square into two right angle triangle.

Where, the sides of the square are the legs of the triangle and diagonal is the hypotenuse of the triangle.

$x^2+x^2=(100\sqrt{2})^2$

$2x^2=(100\sqrt{2})^2$

$x=100$

Hence, the side of the square is 100 ft.

The perimeter of the square is $4s$ where s is the side of square.

$4(100)=400$

Hence, the perimeter of the garden is 400 feet.

5 0

3 years ago

What is 181x182 if you guess this right you get a follow and a thank you and you can get 30$

Harlamova29_29 [7]

Answer: c[p(g)] = 0.896g

Step-by-step explanation:

8 0

3 years ago

A ladder 10 feet long rests against a vertical wall. Initially, the top of the ladder is 8 feet above the ground. If the top of

lora16 [44]

Step-by-step explanation:

Let vertical height of ladder from ground be y and

horizontal distance of the base of the ladder from the wall be x respectively.

Length of the ladder = l (constant) = 10 ft

Using Pythagoras theorem:

${l}^{2} = {y}^{2} + {x}^{2}$

Differentiate both sides w.r.t time

$0 = 2y \frac{dy}{dt} + 2x \frac{dx}{dt}$

$y \frac{dy}{dt} + x \frac{dx}{dt} = 0$

We know that (After 1 sec, y = 6 ft and x = 8 ft ; dy/dt = 2 ft/sec)

$6\times 2 + 8\frac{dx}{dt} = 0$

$\frac{dx}{dt} = - 1.5 ft \: per \: sec$

( Ignore - ive sign)

Therefore, bottom of the ladder is sliding away from the wall at a speed of 1.5 ft/sec one second after the ladder starts sliding.

8 0

3 years ago

Joshua's goal is to sell more than 20 items at a farmers' market. So far, he has sold 6 items. Each of his customers buys 2 item

Volgvan

6 + 2c greater than 20. c Must be at least 8 customers.

5 0

2 years ago