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lesya692 [45]
2 years ago
12

What is the sum (6x^3 – 5x^2 + 3x – 5) + (8x^4 + 3x^3 + 5x^2 + x + 4)?

Mathematics
2 answers:
nadezda [96]2 years ago
7 0

Answer:

8x^4+9x^3+4x-1

Step-by-step explanation:

(6x^3 – 5x^2 + 3x – 5) + (8x^4 + 3x^3 + 5x^2 + x + 4)

Group like terms

8x^4+6x^3+3x^3-5x^2+5x^2+3x+x-5+4

8x^4+9x^3+4x-1

TiliK225 [7]2 years ago
6 0

Answer:

\left(6x^3-5x^2+3x-5\right)+\left(8x^4+3x^3+5x^2+x+4\right)

Combine like terms

=8x^4+6x^3+3x^3-5x^2+5x^2+3x+x-5+4

Add: -5x²+5x²=0

=8x^4+6x^3+3x^3+3x+x-5+4

Now add 6x³+3x³=9x³

=8x^4+9x^3+3x+x-5+4

Add like terms 3x +x=4x

=8x^4+9x^3+4x-5+4

Now add -5+4=-1

=8x^4+9x^3+4x-1

<u>OAmalOHopeO</u>

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Answer:

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Use y=2.5x+65 to find x when y=75
uranmaximum [27]

Answer:

The value of x is 4

Step-by-step explanation:

y = 2.5x + 65; y = 75

Now, Substitute

y = 2.5x + 65

75 = 2.5x + 65

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6 0
2 years ago
PLEASE HELP<br>L has y-intercept (0,5) and is perpendicular to the line with equation y=1/3x+1
marin [14]

Answer:

y=-3x+5

Explanation:

Given a line L such that:

• L has y-intercept (0,5); and

,

• L is perpendicular to the line with equation y=(1/3)x+1.

We want to find the equation of the line in the slope-intercept form.

The slope-intercept form of the equation of a straight line is given as:

\begin{equation} y=mx+b\text{ where }\begin{cases}m={slope} \\ b={y-intercept}\end{cases} \end{equation}

Comparing the given line with the form above:

y=\frac{1}{3}x+1\implies Slope,m=\frac{1}{3}

Next, we find the slope of the perpendicular line L.

• Two lines are perpendicular if the product of their slopes is -1.

Let the slope of L = m1.

Since L and y=(1/3)x+1 are perpendicular, therefore:

\begin{gathered} m_1\times\frac{1}{3}=-1 \\ \implies Slope\text{ of line L}=-3 \end{gathered}

The y-intercept of L is at (0,5), therefore:

y-intercept,b=5

Substitute the slope, m=-3, and y-intercept, b=5 into the slope-intercept form.

\begin{gathered} y=mx+b \\ y=-3x+5 \end{gathered}

The equation of line L is:

y=-3x+5

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Answer:

he can buy 30

Step-by-step explanation:

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