Answer:
False. See te explanation an counter example below.
Step-by-step explanation:
For this case we need to find:
for all
and for
in the Markov Chain assumed. If we proof this then we have a Markov Chain
For example if we assume that
then we have this:

Because we can only have
if we have this:
, from definition given 
With
we have that 
So based on these conditions
would be 1 with probability 1/2 from the definition.
If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.
Let's assume that
for this case in order to satisfy the definition then 
But on this case that means
and on this case the probability
, so we have a counter example and we have that:
for all
so then we can conclude that we don't have a Markov chain for this case.
Answer:
(2x+3) y (3x+5)
Step-by-step explanation:
For this exercise we have that the volume is
V = 6x ^ 3 + 31X ^ 2 + 53x + 30
H = X + 2
The formula for the Volume its
V = H * L * W
for find L and W (width and length) we divide V / H = L * W
So,

this division is in the attachment
so, L * W = (2x + 3) * (3x + 5)
Answer:
A.200
Step-by-step explanation:
Answer:

And if we count the number of zeros before the number 7, we can rewrite the number like this:

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Step-by-step explanation:
For this case we have the following number given:

And if we count the number of zeros before the number 7, we can rewrite the number like this:

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Answer:
O A.
Step-by-step explanation:
<u>Option A</u> identifies two angles (sufficient for similarity) and one side, sufficient (with similarity) for congruence. The applicable congruence theorem is AAS.
<u>Option B</u> identifies two sides and the angle not between them. The two triangles will be congruent in that case only if the angle is opposite the longest side, which is <u>not true</u> in general.
<u>Option C</u> same deal as Option A.
<u>Option D</u> identifies three congruent angles, which will prove the triangles similar, but not necessarily congruent.