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2 years ago

PLEASE ANSWER ASAP!!

Mathematics

1 answer:

KATRIN_1 [288]2 years ago

6 0

Answer:

See below.

Step-by-step explanation:

The corners of the square are:

(-7, 6) which becomes (-6, 7)

(-2, 6) which becomes (-6, 2)

(-7, 1) which becomes (-1, 7)

(-2, 1) which becomes (-1, 2)

From the top left corner of the square, ABCD rotates to ACDB (clockwise), so Darla is correct.

The new square is in the same quadrant as the original, so quadrant 2.

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Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10

Alenkasestr [34]

Answer: The correct option is (D) SET 4.

Step-by-step explanation: We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

Perpendicular² + Base² = Hypotenuse².

Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.

SET 1 : 14 cm, 5 cm, 6 cm.

We have

$5^2+6^2=25+36=61,\\\\14^2=196.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 2 : 8 in., 12 in., 20 in.

We have

$8^2+12^2=64+144=208,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 3 : 10 mm, 20 mm, 30 mm.

We have

$10^2+20^2=100+400=500,\\\\30^2=900.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 4 : 12 ft, 16 ft, 20 ft.

We have

$12^2+16^2=144+256=400,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² = Hypotenuse².

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

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2 years ago

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A farmer has 1,200 feet of fencing and wants to fence off a rectangular field that borders a straight river. He needs no fence a

iVinArrow [24]

Yay, derivitives
I'mma ignore that x is the shorter side because I don't know which one has to be shorter yet

we need to find the max area
but with 3 sides

area=LW
let's say the sides are z and y
zy=area

and the relatiionship between them is
hmm,
z+2y=1200
because one side has no fencing
so
z+2y=1200
solve for z
z=1200-2y
sub for z in other

(1200-2y)(y)=area
expand
1200y-2y²=area
take derivitive
1200-4y=dy/dx area
max is where dy/dx goes from positive to negative
solve for where dy/dx=0
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1200=4y
300=y

at y<300, dy/dx<0
at y>300, dy/dx>0
so at y=300, that is the max

then
z=1200-2y
z=1200-2(300)
z=1200-600
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so then
z=600
y=300
300<600

so the shorter side would be y

so then we see our choices and noticed that
erm
I think it is f(x)=1200x-2x²
takind the derivitive yeilds none of the others

so ya, you are right

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Can I get a little help here?

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Answer:

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s = the shirt price

Since Jason bought 3 shirts, we need to multiply the 3 shirts by its value which would be 3s. He has a coupon for $10 off, so we need to subtract 3s by 10. Since he spent $65 we need to set the whole equation equal to 65 and out final answer would be 3s - 10 = 65.

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