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slamgirl [31]
2 years ago
6

Which of the following sets of points are NOT coplanar?

Mathematics
1 answer:
disa [49]2 years ago
7 0

admins, pls delete this, I messed up and don't know how

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Find the area of the figure. use 3.14 for pi
Elodia [21]

Answer:

33.29

Step-by-step explanation:

A=πr^2

A=π2^2=12.57

12.57/2=6.29

7-4=3

3x2=6

6/2=3

4x6=24

6.29+3+24=33.29

3 0
2 years ago
Read 2 more answers
What is the value of x<br> 2x+3y=45 <br> x+y=10
Volgvan
Assuming this is a system of equations, here is how to find x. 

2x + 3y = 45
x + y = 10 

Multiply x + y = 10 by 2 so you are able to use the elimination method.

2x + 3y = 45
2x + 2y = 20

Subtract.

y = 25

Now that we've found y, we can plug it in to find x. 

x + 25 = 10

Subtract 25 from both sides.

x = -15
4 0
3 years ago
Can someone help me with 17, 19 and 21? I don't understand!
vfiekz [6]
The first number in parenthesis is the x axis the second is they the first number in the parenthesis is the x axis the second is the y axis you have to make an equation in y=my+b form and I can’t see what I’m typing due to your picture so sorry
5 0
3 years ago
Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t
Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let \sigma_{1}^{2} be the variance for the population of weight gains for rats given a low dose, and \sigma_{2}^{2} the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2} vs H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}. We have that the sample standard deviation for n_{2} = 22 female control rats was s_{2} = 28 g and for n_{1} = 18 female low-dose rats was s_{1} = 51 g. So, we have observed the value

F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176 which comes from a F distribution with n_{1} - 1 = 18 - 1 = 17 degrees of freedom (numerator) and n_{2} - 1 = 22 - 1 = 21 degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

8 0
3 years ago
17 = -47 + 6.98x. solve the equation. round your answer to the nearest hundredth
shutvik [7]
Solving it and nearing it to the hundredth would be 9.169 :)
6 0
2 years ago
Read 2 more answers
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