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3 years ago

What is equivalent to 20r+60t

Mathematics

2 answers:

faltersainse [42]3 years ago

6 0

Answer:

1r + 3t

to find the answer, all you have to do is simplify both numbers by the highest common factor which is 20.

pickupchik [31]3 years ago

6 0

I just would put 20(r+3t)

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The tree in johns backyard is 7 meters high. How high is it in in centimeters?

GenaCL600 [577]

Answer:

700 meters

Step-by-step explanation:

multiply the length value by 10

8 0

2 years ago

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2(x + 3)=x - 4<br>help me

Irina18 [472]

Answer:

x = -10

Step-by-step explanation:

2(x+3) = x-4 --> multiply (x+2) times 2

2x+6 = x - 4 --> subtract x from both sides

x+6 = -4 --> subtract 6 from both sides

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2 years ago

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Find the approximate circumference of a circle with a diameter of 100 yards.

elixir [45]

Answer:

D. 314 yds

Step-by-step explanation:

Given:

Diameter = 100 yds

Required;

Circumference of the circle

Solution:

Circumference of circle = πd

Plug in the value

Circumference = π × 100

= 314 yds (nearest whole number)

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3 years ago

A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (

NikAS [45]

Answer:

A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.

another way is

This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.

So,

(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA

Step-by-step explanation:

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2 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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1 year ago