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Leto [7]
2 years ago
10

Which is the range of the discrete function G(x)?

Mathematics
1 answer:
Shkiper50 [21]2 years ago
8 0
The range of the discrete function is C- 2,5,9
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Help me please I need to do this
Blizzard [7]

Consider the attached tree.

You start from the root, and with each level you create a sub-branch for each of the choices you have.

So, the root has two children, white and multigrain bread.

Each of those children has three children, because you have three meat choices

Each of those children has two children, because you have two cheese choices.

Then, you identify all the sandwiches by choosing a leaf, and read the label that lead you there.

For example, leaf number 4 represents a sandwich with white bread, turkey and provolone.

8 0
3 years ago
Geo help pls! 20 PTS
Mice21 [21]
2 is 160, 3 is 10 so it’ll add to 180
3 0
3 years ago
1 point<br> 13. Use the order of operations to simplify the expression: 24 - 5.<br> (-8) + (7 - 11)
ANTONII [103]

Answer:

50

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Use the pythagorean theorem to prove that this point lies on the unit circle. Find csc(0) where 0=-120.
exis [7]

By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.

<h3>How to prove this point lies on the unit circle?</h3>

In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:

Reference angle = 180 - θ

Reference angle = 180 - 120

Reference angle = 60°.

For the coordinates, we have:

sin(-120) = -sin(60) = -1/2.

cos(-120) = -cos(60) = -√3/2.

By applying Pythagorean theorem, we have:

z² = x² + y²

z = √((-1/2)² + (-√3/2)²)

z = √(1/4 + 3/4)

z = √1

z = 1.

Read more on unit circle here: brainly.com/question/9797740

#SPJ1

4 0
2 years ago
Which is not an equation of the line that passes through the points (1, 1) and (5, 5)?
maria [59]

(1,\ 1)\to x_1=1,\ y_1=1\to x_1=y_1\\\\(5,\ 5)\to x_2=5,\ y_2=5\to x_2=y_2\\\\\text{Therefore we have the equation}\ y=x\\\\\text{subtract y from both sides}\\\\\boxed{x-y=0\to\boxed{B}}\to\boxed{y-x=0\to\boxed{A.}}\\\\Answer:\ C.\ -x-y=0

8 0
3 years ago
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