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3 years ago

Robert is writing a paper he can wright 1/3 of a page in 1/2 of an hour

Mathematics

1 answer:

Marina CMI [18]3 years ago

7 0

Answer:

in 1/2 hour 1/3 of the page is done

in 1 hour 2/3 of the page is done

in 1 and 1/2 hour 3/3 pages are done

Step-by-step explanation:

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Four less than the product of 6 and a number n is -30. What is the number? _____

kherson [118]

Answer:

Step-by-step explanation:

7 0

3 years ago

mr.mcbride asks students to find the volume of the triangular pyramid below. which student wrote the correct expression for the

Black_prince [1.1K]

Given:

Given that the height of the pyramid is 20 inches.

The sides of the triangle are 9 in, 12 in and 15 in.

The expression for the area of the base written by JO is $\frac{1}{2}(9 \cdot 15)$

The expression for the area of the base written by MAE is $\frac{1}{2}(9 \cdot 12)$

We need to determine the correct expression for the area of the base written by the student.

Expression for the area of the base:

The area of the base of the triangular prism can be determined using the formula,

$B=\frac{1}{2}bh$

where b is the base of the triangle and h is the height of the triangle.

From the figure, the base of the triangle is 9 inches and the height of the triangle is 12 inches.

Substituting in the above formula, we get;

$B=\frac{1}{2}(9 \cdot 12)$

Thus, the correct expression for the area of the base is $B=\frac{1}{2}(9 \cdot 12)$

Hence, the expression wrote by MAE is correct.

8 0

3 years ago

A Statistics professor has observed that for several years students score an average of 114 points out of 150 on the semester ex

kirill [66]

Answer:

Reject $H_0$ . The change is statistically significant. The software does appear to improve exam scores.

Step-by-step explanation:

We are given that a Statistics professor has observed that for several years students score an average of 114 points out of 150 on the semester exam. The software is expensive, and the salesman offers to let the professor use it for a semester to see if the scores on the final exam increase significantly.

In the trial course that used this software, 218 students scored an average of 117 points on the final with a standard deviation of 8.7 points.

Let $\mu$ = mean scores on the final exam.

SO, Null Hypothesis, $H_0$ : $\mu \leq$ 114 points {means that the mean scores on the final exam does not increases after using software}

Alternate Hypothesis, $H_A$ : $\mu$ > 114 points {means that the mean scores on the final exam increase significantly after using software}

The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average points = 117 points

s = sample standard deviation = 8.7 points

n = sample of students = 218

So, test statistics = $\frac{117-114}{\frac{8.7}{\sqrt{218} } }$ ~ $t_2_1_7$

= 5.091

Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_2_1_7$ > 5.091) = Less than 0.05%

Since, in the question we are not given with the level of significance at which hypothesis can be tested, so we assume it to be 5%. Now at 5% significance level, the t table gives critical value of 1.645 at 217 degree of freedom for right-tailed test. Since our test statistics is higher than the critical value of t as 5.091 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the change is statistically significant. The software does appear to improve exam scores.

3 0

3 years ago

3(3x-4)-7=8 Solve for x and explain

puteri [66]

Answer:

x=8

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What number is between 200 and 300.