Answer:4th: 729 6th: 6561
Step-by-step explanation: Sorry, I’m not 100% sure but I will try to help out: :)
So 2nd term is 81 and you want the 4th and 6th term.
Common ratio is 3
I approached it like this:
81x3=243 (3rd Term)
243x3=729 (4th Term)
729x3=2187 (5th Term)
2187x3=6561 (6th Term)
So if this isn’t the correct way the only other way I can think to approach this is
81+3=84(3rd Term)
84+3=87(4th Term)
87+3=90(5th Term)
90+3=93(6th Term)
Hope this helps
Simple answer L4 and L1<span />
X = 14
1/2 of 14 = 7
7 + 13 = 20
Answer:
k =
Step-by-step explanation:
Fisherman noticed a stretch in the spring = 'b' centimetres
Weight of the fish = a kilograms
If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,
F = kΔx
Where k = spring constant
Δx = stretch in the spring
F = weight applied
F = mg
Here 'm' = mass of the fish
g = gravitational constant
F = a(9.8)
= 9.8a
Δx = b centimetres = 0.01b meters
Therefore, 9.8a = k(0.01b)
k =
k =
Therefore, spring constant of the spring will be determined by the expression, k =