Answer:
<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>
Step-by-step explanation:
We know
for any real value of <em>a</em>.
|a| = b > 0 - <em>two solutions: </em>a = b or a = -b
|a| = 0 - <em>one solution: a = 0</em>
|a| = b < 0 - <em>no solution</em>
<em />
|x + 6| - 4 = c
for c = 5:
|x + 6| - 4 = 5 <em>add 4 to both sides</em>
|x + 6| = 9 > 0 <em>TWO SOLUTIONS</em>
for c = -10
|x + 6| - 4 = -10 <em>add 4 to both sides</em>
|x + 6| = -6 < 0 <em>NO SOLUTIONS</em>
<em></em>
Calculate the solutions for c = 5:
|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9 <em>subtract 6 from both sides</em>
x = 3 or x = -15
Step-by-step explanation:
Converse: If the quadrilateral is a square, then the quadrilateral has four congruent sides and angles.
Answer:
y = -17
Step-by-step explanation:
5 + 3(y - 4) = 5(y + 2) - y Distribute
5 + 3y -12 = 5y + 10 - y Combine like terms
-7 + 3y = 4y + 10
+7 +17 Add 17 to both sides
3y = 4y + 17
-4y -4y Subtract 4y from both sides
-y = 17 Divide both sides by -1
y = -17
If this answer is correct, please make me Brainliest!
Answer:
6 and -14
Step-by-step explanation:
Area of the triangle = 1/2 ab
42 = 1/2 (x)(x+8)
42 *2 = x(x+8)
84 = x²+8x
x²+8x-84 = 0
x²+14x-6x-84 = 0
x(x+14)-6(x+14) = 0
x-6 = 0 and x+14 = 0
x = 6 and -14
Hence the values of x are 6 and -14
