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3 years ago

What Ticket prices will result in an income of $0?

Mathematics

1 answer:

Viefleur [7K]3 years ago

7 0

100p-5p^2 = 0

Factor out 5p out of 100p and -5p^2:

5p(20) + 5p(-p) = 0

Factor:

5p(20-p)=0

Divide each term by 5:

p = 0

Set 20-p to 0 and solve for p:

p = 20

The answer is 0, 20

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An airplane flies 2700 miles to Los Angeles to NYC. When the plane flies back to LA, is it flying in a negative direction? use a

dolphi86 [110]

Answer:

Distance = abs(-1700)

Distance = 1700 miles

Step-by-step explanation:

NYC is located East of Los Angels.

The Airplane flies from Los Angeles to the left direction from NYC.

Which is negative direction.

Therefore, distance = -1700

Here the distance cannot be negative even though if it flies in negative direction.

Therefore, we use the absolute value.

The absolute value of a number is always positive.

So, distace = abs( -1700)

Distance = 1700 miles.

Hope this will help you understand the concept.

Thank you.

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3 years ago

(10) Does the table show a proportional relationship?

Blababa [14]

Answer:

Step-by-step explanation:

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3 years ago

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At a sale, suits were sold for $116 each. This price was 58% of a suit's original price. How much did a suit originally cost?

Fudgin [204]

To find the original price first put the % into decimal form.

58% is 0.58.

Then divide the discounted price ($116) by the % in decimal form:

116 / 0.58

Original price is $200.00

4 0

3 years ago

Let f of x equals the integral from x to 1 of the square root of the quantity of 1 plus t squared . use your calculator to find

ollegr [7]

Analytically, it will be

-√(1+1²) = -√2

The calculator shows it to be -1.41421356237

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= -√2 to 12 significant digits.

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3 years ago

An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden

Butoxors [25]

Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0$

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

$p_1=X_1/n_1=180/500=0.36$

The sample 2, of size n2=600 has a proportion of p2=0.25.

$p_1=X_1/n_1=150/600=0.25$ .

The difference between proportions is (p1-p2)=0.11.

$p_d=p_1-p_2=0.36-0.25=0.11$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{180+150}{500+600}=\dfrac{330}{1100}=0.3$

The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=2\cdot P(t>3.964)=0.000078$

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.0277=0.0544$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.11-0.0544=0.05561\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.11+0.0544=0.16439$

The 95% confidence interval for the population mean is (0.0556, 0.1644).

5 0

3 years ago